CUET · PHYSICS · PYQ PAPER 2025
A 200-turn coil of self-inductance 20 mH carries a current of 4 mA. The magnetic flux linked with each turn of the coil is:
- A \(16 \times 10^{-3} \text{ Wb} \)
- B \( 8 \times 10^{-5} \text{ Wb} \)
- C \( 4\times 10^{-7} \text{ Wb} \)
- D \(2 \times 10^{-6} \text{ Wb} \)
Answer & Solution
Correct Answer
(C) \( 4\times 10^{-7} \text{ Wb} \)
Step-by-step Solution
Detailed explanation
\( \Phi_{\text{each turn}} = \frac{LI}{N} \) \( \Phi_{\text{each turn}} = \frac{(20 \times 10^{-3} \text{ H})(4 \times 10^{-3} \text{ A})}{200} \) \( \Phi_{\text{each turn}} = 4 \times 10^{-7} \text{ Wb} \)
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