CUET · PHYSICS · PYQ PAPER 2023
A 20 m long horizontal wire extends from North-East to South-West. It is falling down with a speed of \(4 \mathrm{~m} / \mathrm{s}\) horizontally. The horizontal components of the earth's magnetic field is \(0.4 \times 10^{-4}\) T. Find the value of induced current in the wire if the resistance of wire is \(2 \Omega\) is :
- A 1.13 mA
- B 2.26 mA
- C 1.6 mA
- D 0.8 mA
Answer & Solution
Correct Answer
(A) 1.13 mA
Step-by-step Solution
Detailed explanation
\( \varepsilon = B_H L v \sin\theta \) \( \varepsilon = (0.4 \times 10^{-4} \text{ T})(20 \text{ m})(4 \text{ m/s}) \sin(45^\circ) = 32 \times 10^{-4} \times \frac{1}{\sqrt{2}} \text{ V} = 16\sqrt{2} \times 10^{-4} \text{ V} \) \( I = \frac{\varepsilon}{R} \)…
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