CUET · MATHS · PYQ PAPER 2025
\(\int \frac{\sin x-x \cos x}{x(x+\sin x)} d x=\) (where \(C\) is an arbitrary constant)
- A \(\log \left|\frac{x}{x-\sin x}\right|+C\)
- B \(\log \left|\frac{x}{x+x \sin x}\right|+C\)
- C \(\log \left|\frac{x}{x+\sin x}\right|+C\)
- D \(\log \left|\frac{x+\sin x}{x}\right|+C\)
Answer & Solution
Correct Answer
(C) \(\log \left|\frac{x}{x+\sin x}\right|+C\)
Step-by-step Solution
Detailed explanation
Let \( f(x) = \frac{x}{x+\sin x} \). \( f'(x) = \frac{(x+\sin x)(1) - x(1+\cos x)}{(x+\sin x)^2} = \frac{\sin x - x\cos x}{(x+\sin x)^2} \). \( \int \frac{\sin x-x \cos x}{x(x+\sin x)} d x = \int \frac{\sin x-x \cos x}{(x+\sin x)^2} \cdot \frac{x+\sin x}{x} d x \).…
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