CUET · MATHS · PYQ PAPER 2023
\(\int \frac{x+\sqrt{x}}{2 \sqrt{x}} d x=\)
- A \(2 x \sqrt{x}+3 x+C\) (Here \(C\) is an arbitrary constant)
- B \(2 \sqrt{x}+C\) (Here \(C\) is an arbitrary constant)
- C \(x \sqrt{x}+x+C\) (Here \(C\) is an arbitrary constant)
- D \(\frac{x \sqrt{x}}{3}+\frac{x}{2}+C\) (Here \(C\) is an arbitrary constant)
Answer & Solution
Correct Answer
(D) \(\frac{x \sqrt{x}}{3}+\frac{x}{2}+C\) (Here \(C\) is an arbitrary constant)
Step-by-step Solution
Detailed explanation
\(\int \left( \frac{x}{2 \sqrt{x}} + \frac{\sqrt{x}}{2 \sqrt{x}} \right) d x = \int \left( \frac{\sqrt{x}}{2} + \frac{1}{2} \right) d x\) \(= \int \left( \frac{1}{2} x^{1/2} + \frac{1}{2} \right) d x\) \(= \frac{1}{2} \frac{x^{3/2}}{3/2} + \frac{1}{2} x + C\)…
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