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CUET · MATHS · PYQ PAPER 2023

\(\int \frac{x+\sqrt{x}}{2 \sqrt{x}} d x=\)

  1. A \(2 x \sqrt{x}+3 x+C\) (Here \(C\) is an arbitrary constant)
  2. B \(2 \sqrt{x}+C\) (Here \(C\) is an arbitrary constant)
  3. C \(x \sqrt{x}+x+C\) (Here \(C\) is an arbitrary constant)
  4. D \(\frac{x \sqrt{x}}{3}+\frac{x}{2}+C\) (Here \(C\) is an arbitrary constant)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{x \sqrt{x}}{3}+\frac{x}{2}+C\) (Here \(C\) is an arbitrary constant)

Step-by-step Solution

Detailed explanation

\(\int \left( \frac{x}{2 \sqrt{x}} + \frac{\sqrt{x}}{2 \sqrt{x}} \right) d x = \int \left( \frac{\sqrt{x}}{2} + \frac{1}{2} \right) d x\) \(= \int \left( \frac{1}{2} x^{1/2} + \frac{1}{2} \right) d x\) \(= \frac{1}{2} \frac{x^{3/2}}{3/2} + \frac{1}{2} x + C\)…
From CUET
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