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CUET · MATHS · PYQ PAPER 2023

\(\int \frac{x}{x^2+x-12} d x\) is equal to

  1. A \(\frac{3}{7} \log |x-3|+\frac{4}{7} \log |x+4|+C\)
  2. B \(-\frac{3}{7} \log |x-3|+\frac{4}{7} \log |x+4|+C\)
  3. C \(\frac{4}{7} \log |x-3|+\frac{3}{7} \log |x+4|+C\)
  4. D \(\frac{4}{7} \log |x-3|-\frac{3}{7} \log |x+4|+C\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{3}{7} \log |x-3|+\frac{4}{7} \log |x+4|+C\)

Step-by-step Solution

Detailed explanation

\(x^2+x-12 = (x-3)(x+4)\) \(\frac{x}{(x-3)(x+4)} = \frac{A}{x-3} + \frac{B}{x+4}\) \(x = A(x+4) + B(x-3)\) For \(x=3\): \(3 = A(3+4) \Rightarrow A = \frac{3}{7}\) For \(x=-4\): \(-4 = B(-4-3) \Rightarrow B = \frac{4}{7}\)…
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