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CUET · MATHS · PYQ PAPER 2025

\(\int \frac{x}{(x-1)(x-2)} d x\) is equal to (where C is a constant of integration)

  1. A \(\log _e\left|\frac{(x-1)^2}{x-2}\right|+C\)
  2. B \(\log _e\left|\frac{(x-2)^2}{x-1}\right|+C\)
  3. C \(\log _e\left|(x-2)(x-1)^2\right|+C\)
  4. D \(\log _e\left|\frac{x-1}{(x-2)^2}\right|+C\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\log _e\left|\frac{(x-2)^2}{x-1}\right|+C\)

Step-by-step Solution

Detailed explanation

\(\frac{x}{(x-1)(x-2)} = \frac{-1}{x-1} + \frac{2}{x-2}\) \(\int \left( \frac{-1}{x-1} + \frac{2}{x-2} \right) dx = -\log _e |x-1| + 2\log _e |x-2| + C\) \(= \log _e \left| \frac{(x-2)^2}{x-1} \right| + C\)