CUET · MATHS · PYQ PAPER 2025
\(\int \frac{\left(x^4-x\right)^{1 / 4}}{x^5} d x\) is equal to
- A \(\frac{4}{15}\left(1-\frac{1}{x^3}\right)^{5 / 4}+C: C\) is a constant of integration
- B \(\frac{4}{3}\left(1-\frac{1}{x^3}\right)^{5 / 4}+C: C\) is a constant of integration
- C \(\frac{4}{15}\left(1-\frac{1}{x^3}\right)^{3 / 4}+C: C\) is a constant of integration
- D \(\frac{4}{15}\left(1-\frac{1}{x^3}\right)^{1 / 5}+C: C\) is a constant of integration
Answer & Solution
Correct Answer
(A) \(\frac{4}{15}\left(1-\frac{1}{x^3}\right)^{5 / 4}+C: C\) is a constant of integration
Step-by-step Solution
Detailed explanation
\(\int \frac{\left(x^4\left(1-x^{-3}\right)\right)^{1 / 4}}{x^5} d x = \int \frac{x\left(1-x^{-3}\right)^{1 / 4}}{x^5} d x = \int \frac{\left(1-x^{-3}\right)^{1 / 4}}{x^4} d x\) Let \(u = 1-x^{-3}\), then \(du = 3x^{-4} dx = \frac{3}{x^4} dx\), so…
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