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CUET · MATHS · PYQ PAPER 2023

\(\int\left(x+\frac{1}{x}\right)^2 d x\) equals :

  1. A \(\frac{x^3}{3}+\frac{1}{x}-2 x+c\)
  2. B \(\frac{x^3}{3}-\frac{1}{x}+2 x+c\)
  3. C \(\frac{x^3}{3}-\frac{1}{x}-2 x+c\)
  4. D \(\frac{x^3}{3}+\frac{1}{x}+2 x+c\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{x^3}{3}-\frac{1}{x}+2 x+c\)

Step-by-step Solution

Detailed explanation

\( \int\left(x+\frac{1}{x}\right)^2 d x = \int\left(x^2+2+\frac{1}{x^2}\right) d x \) \( = \frac{x^3}{3} + 2x - \frac{1}{x} + c \)