CUET · MATHS · PYQ PAPER 2023
\(\int \frac{x \sin ^{-1} x}{\sqrt{1-x^2}} d x=\)
- A \(\sqrt{1-x^2} \cos x+x+C\)
- B \(\sqrt{1-x^2} \sin x+x+C\)
- C \(\sqrt{1-x^2} \sin ^{-1} x+x+C\)
- D \(-\sqrt{1-x^2} \sin ^{-1} x+x+C\)
Answer & Solution
Correct Answer
(D) \(-\sqrt{1-x^2} \sin ^{-1} x+x+C\)
Step-by-step Solution
Detailed explanation
Let \(u = \sin^{-1} x\) and \(dv = \frac{x}{\sqrt{1-x^2}} dx\). \(du = \frac{1}{\sqrt{1-x^2}} dx\) \(v = \int \frac{x}{\sqrt{1-x^2}} dx = -\sqrt{1-x^2}\) \(\int u \, dv = uv - \int v \, du\)…
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