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CUET · MATHS · PYQ PAPER 2025

\(\int \frac{(x-1) e^x}{x^2} d x\), \(x > 0\) equals (where C is an arbitrary constant)

  1. A \(x e^x+C\)
  2. B \(\frac{e^x}{x}+C\)
  3. C \(\frac{e^{-x}}{x^2}+C\)
  4. D \(e^x+\frac{1}{x}+C\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{e^x}{x}+C\)

Step-by-step Solution

Detailed explanation

\(\int \frac{(x-1) e^x}{x^2} d x = \int \frac{d}{dx} \left(\frac{e^x}{x}\right) d x = \frac{e^x}{x} + C\)
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