CUET · MATHS · PYQ PAPER 2023
Which of the following is true?
- A \(\int \frac{dx}{x^2 + a^2} = \frac{1}{2a} \log \left|\frac{x-a}{x+a}\right| + c\), where c is an arbitrary constant
- B \(\int \frac{dx}{x^2 - a^2} = \frac{1}{2a} \log \left|\frac{x-a}{x+a}\right| + c\), where c is an arbitrary constant
- C \(\int \frac{dx}{x^2 - a^2} = \frac{1}{2a} \log \left|\frac{x+a}{x-a}\right| + c\), where c is an arbitrary constant
- D \(\int \frac{dx}{x^2 + a^2} = \frac{1}{2a} \log \left|\frac{x+a}{x-a}\right| + c\), where c is an arbitrary constant
Answer & Solution
Correct Answer
(B) \(\int \frac{dx}{x^2 - a^2} = \frac{1}{2a} \log \left|\frac{x-a}{x+a}\right| + c\), where c is an arbitrary constant
Step-by-step Solution
Detailed explanation
\(\int \frac{dx}{x^2 - a^2} = \frac{1}{2a} \log \left|\frac{x-a}{x+a}\right| + c\)
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