CUET · MATHS · PYQ PAPER 2025
Which of the following are NOT correct regarding the equation of tangent and normal to the curve \(y=\frac{x-11}{(x-2)(x-3)}\) at the point, where it cuts the \(x\)-aris?
(A) The point of contact is \((11,0)\).
(B) The equation of tangent is \(x-72 y-11=0\).
(C) The equation of normal is \(7 2 x + y - 1 1 = 0\).
(D) The slope of the tangent at the given point of contact is \(\frac{1}{88}\).
Choose the correct answer from the options given below:
- A (A), (B) and (D) only
- B (B) and (C) only
- C (A), (C) and (D) only
- D (C) and (D) only
Answer & Solution
Correct Answer
(D) (C) and (D) only
Step-by-step Solution
Detailed explanation
\(y=0 \Rightarrow x-11=0 \Rightarrow x=11\). Point: \((11,0)\). \(\frac{dy}{dx} = \frac{(x-2)(x-3) \cdot 1 - (x-11)((x-2)+(x-3))}{((x-2)(x-3))^2}\).…
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