CUET · MATHS · PYQ PAPER 2023
Using the concept of differentials,\(\sqrt{36.6}\) is approximately equal to:
- A 6.05
- B 6.01
- C 6.1
- D 6.5
Answer & Solution
Correct Answer
(A) 6.05
Step-by-step Solution
Detailed explanation
\(f(x) = \sqrt{x}\) \(x = 36, \Delta x = 0.6\) \(f(x) = \sqrt{36} = 6\) \(f'(x) = \frac{1}{2\sqrt{x}}\) \(f'(36) = \frac{1}{2\sqrt{36}} = \frac{1}{12}\) \(\sqrt{36.6} \approx f(x) + f'(x)\Delta x\) \(\sqrt{36.6} \approx 6 + \frac{1}{12}(0.6)\) \(\sqrt{36.6} \approx 6 + 0.05\)…
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