CUET · MATHS · PYQ PAPER 2023
Two tailors A and B earn ₹150 and ₹200 per day respectively. A can stitch 6 shirts and 4 pants per day, while B can stitch 10 shirts and 4 pants per day. If the tailors A and B work for x and y days respectively. To maximize the earning for producing at least 60 shirts and 32 pants, the LPP is:
- A Maximize \(Z = 150x + 200y\), subject to \(6x + 10y \ge 60, 4x + 4y \ge 32, x, y \ge 0\)
- B Maximize \(Z = 150x + 200y\), subject to \(6x + 10y \le 60, 4x + 4y \le 32, x, y \ge 0\)
- C Maximize \(Z = 150x + 200y\), subject to \(6x + 4y \ge 60, 10x + 4y \ge 32, x, y \ge 0\)
- D Marimize \(Z=150 x+200 y\), subject to \(6 x+10 y \geq 60,4 x+4 y \leq 32, x, y \geq 0\)
Answer & Solution
Correct Answer
(A) Maximize \(Z = 150x + 200y\), subject to \(6x + 10y \ge 60, 4x + 4y \ge 32, x, y \ge 0\)
Step-by-step Solution
Detailed explanation
Maximize \(Z = 150x + 200y\) Subject to: \(6x + 10y \ge 60\) \(4x + 4y \ge 32\) \(x, y \ge 0\)
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