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CUET · MATHS · PYQ PAPER 2025

Two persons A and B throw a die alternately till one of them gets a six and wins the game. If A begins, then the probabilities of winning of A and B respectively are

  1. A \(\frac{1}{6}, \frac{1}{6}\)
  2. B \(\frac{2}{3}, \frac{1}{3}\)
  3. C \(\frac{6}{11}, \frac{5}{11}\)
  4. D \(\frac{5}{11}, \frac{6}{11}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{6}{11}, \frac{5}{11}\)

Step-by-step Solution

Detailed explanation

\( P(\text{success}) = \frac{1}{6}, P(\text{failure}) = \frac{5}{6} \) \( P(\text{A wins}) = \frac{P(\text{success})}{1 - (P(\text{failure}))^2} \)…
From CUET
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