CUET · MATHS · PYQ PAPER 2025
Two persons A and B throw a die alternately till one of them gets a 'three' and wins the game. The probability of A's winning if A starts first is :
- A \(\frac{6}{11}\)
- B \(\frac{1}{6}\)
- C \(\frac{5}{6}\)
- D \(\frac{5}{11}\)
Answer & Solution
Correct Answer
(A) \(\frac{6}{11}\)
Step-by-step Solution
Detailed explanation
Let \( P(S) \) be the probability of getting a 'three' = \( \frac{1}{6} \). Let \( P(F) \) be the probability of not getting a 'three' = \( 1 - \frac{1}{6} = \frac{5}{6} \). Probability of A winning,…
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