CUET · MATHS · PYQ PAPER 2024
Two parallel plate capacitors of capacitances \(2 \mu F\) and \(3 \mu F\) are joined in series and connected to a battery of \(V\) volts. The values of potential across the two capacitors V1 and V2 and energy stored in them U1 and U2 are related as :
- A \(\frac {V _2}{ V _1} = \frac{U_2}{U_1}=\frac {2}{3} \)
- B \(\frac {V _2}{ V _1} = \frac{U_2}{U_1}=\frac {3}{2} \)
- C \(\frac {V _2}{ V _1}= \frac {2}{3}, \frac{U_2}{U_1}=\frac {3}{2} \)
- D \(\frac {V _2}{ V _1}= \frac {3}{2}, \frac{U_2}{U_1}=\frac {2}{3} \)
Answer & Solution
Correct Answer
(A) \(\frac {V _2}{ V _1} = \frac{U_2}{U_1}=\frac {2}{3} \)
Step-by-step Solution
Detailed explanation
\(C_1 V_1 = C_2 V_2\) \(2 V_1 = 3 V_2 \implies \frac{V_2}{V_1} = \frac{2}{3}\) \(U = \frac{Q^2}{2C}\) \(\frac{U_2}{U_1} = \frac{C_1}{C_2}\) \(\frac{U_2}{U_1} = \frac{2}{3}\)
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