CUET · MATHS · PYQ PAPER 2024
Two charged particles, placed at a distance d apart in vacuum, exert a force F on each other. Now, each of the charges is doubled. To keep the force unchanged, the distance between the charges should be changed to :
- A 4d
- B 2d
- C d
- D \(d / 2\)
Answer & Solution
Correct Answer
(A) 4d
Step-by-step Solution
Detailed explanation
\( F = k \frac{q_1 q_2}{d^2} \) \( F = k \frac{(2q_1)(2q_2)}{(d')^2} = k \frac{4q_1 q_2}{(d')^2} \) \( \frac{1}{d^2} = \frac{4}{(d')^2} \) \( (d')^2 = 4d^2 \) \( d' = 2d \)
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