CUET · MATHS · PYQ PAPER 2023
Two biased dice are thrown together. For the first die \(P(6)=1 / 2\), other scores are equally likely. While for the second die, \(P (1)=2 / 5\) and other scores are equally likely then the mean for the probability distribution of 'the number of ones seen', will be
- A 6/5
- B 3/5
- C 4/5
- D 1/2
Answer & Solution
Correct Answer
(D) 1/2
Step-by-step Solution
Detailed explanation
\(P(X_1=1) = (1 - 1/2) / 5 = 1/10\) \(P(X_2=1) = 2/5\) \(E[\text{ones}] = E[N_1] + E[N_2]\) \(E[\text{ones}] = P(X_1=1) + P(X_2=1)\) \(E[\text{ones}] = 1/10 + 2/5\) \(E[\text{ones}] = 1/10 + 4/10 = 5/10 = 1/2\)
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