CUET · MATHS · PYQ PAPER 2023
There are two values of a for which the determinant, \(\Delta = \begin{vmatrix} 1 & -2 & 5 \\ 0 & a & -1 \\ 0 & 4 & 2a \end{vmatrix} = 86\), then the sum of these values of a is:
- A \(\sqrt{41}\)
- B \(0\)
- C \(-\sqrt{41}\)
- D \(2\sqrt{41}\)
Answer & Solution
Correct Answer
(B) \(0\)
Step-by-step Solution
Detailed explanation
\( \Delta = 1(a \cdot 2a - (-1) \cdot 4) = 2a^2 + 4 \) \( 2a^2 + 4 = 86 \) \( 2a^2 = 82 \) \( a^2 = 41 \) \( a = \pm \sqrt{41} \) \( \text{Sum} = \sqrt{41} + (-\sqrt{41}) = 0 \)
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