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CUET · MATHS · PYQ PAPER 2023

The volume of a cube is increasing at the rate of \(27 cm^3 / s\). How fast is the surface area increasing when the length of the cube is 12 cm ?

  1. A \(9 cm^2 / s\)
  2. B \(\frac{9}{4} cm^2 / s\)
  3. C \(\frac{4}{9} cm^2 / s\)
  4. D \(\frac{9}{2} cm^2 / s\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(9 cm^2 / s\)

Step-by-step Solution

Detailed explanation

\( \frac{dV}{dt} = 3s^2 \frac{ds}{dt} \) \( \frac{dA}{dt} = 12s \frac{ds}{dt} = 12s \left( \frac{1}{3s^2} \frac{dV}{dt} \right) = \frac{4}{s} \frac{dV}{dt} \) \( \frac{dA}{dt} = \frac{4}{12} (27) = 9 cm^2/s \)