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CUET · MATHS · PYQ PAPER 2023

The vector equation of the plane which is at a distance of 6 units from the origin and has \(2,-1,2\) as the direction ratios of normal to it, is :

  1. A \(\vec{r} \cdot(2 \hat{i}-\hat{j}+2 \hat{k})=18\)
  2. B \(\vec{r} \cdot(2 \hat{i}-\hat{j}+2 \hat{k})=6\)
  3. C \(\vec{r} \cdot(\hat{i}+\hat{j}+\hat{k})=18\)
  4. D \(\vec{r} \cdot(\hat{i}+\hat{j}+\hat{k})=6\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\vec{r} \cdot(2 \hat{i}-\hat{j}+2 \hat{k})=18\)

Step-by-step Solution

Detailed explanation

Given normal vector \(\vec{n} = 2\hat{i} - \hat{j} + 2\hat{k}\). Magnitude of normal \(\left|\vec{n}\right| = \sqrt{2^2 + (-1)^2 + 2^2} = \sqrt{4+1+4} = \sqrt{9} = 3\). Distance from origin \(p = 6\). The vector equation of the plane is…