CUET · MATHS · PYQ PAPER 2025
The vector equation of line passing through (2, -1, 3) and perpendicular to the lines \(\frac{x-2}{3}=\frac{y-1}{1}=\frac{z+2}{2} \quad\) and \(\quad \frac{x+3}{-4}=\frac{y-5}{-3}=\frac{z+1}{2}\)
(Here \(\lambda\) is a parameter)
- A \(\vec{r}=(2 \hat{i}-\hat{j}+3 \hat{k})+\lambda(8 \hat{i}-14 \hat{j}-5 \hat{k})\)
- B \(\vec{r}=(-2 \hat{i}+\hat{j}-3 \hat{k})+\lambda(8 \hat{i}-14 \hat{j}-5 \hat{k})\)
- C \(\vec{r}=(-8 \hat{i}-14 \hat{j}-5 \hat{k})+\lambda(-2 \hat{i}+\hat{j}+3 \hat{k})\)
- D \((8 \hat{i}-14 \hat{j}-5 \hat{k})+\lambda(2 \hat{i}-\hat{j}+3 \hat{k})\)
Answer & Solution
Correct Answer
(A) \(\vec{r}=(2 \hat{i}-\hat{j}+3 \hat{k})+\lambda(8 \hat{i}-14 \hat{j}-5 \hat{k})\)
Step-by-step Solution
Detailed explanation
Direction vectors of given lines: \( \vec{b_1} = 3\hat{i} + \hat{j} + 2\hat{k} \), \( \vec{b_2} = -4\hat{i} - 3\hat{j} + 2\hat{k} \) Direction vector of required line:…
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