CUET · MATHS · PYQ PAPER 2025
The vector equation of line passing through \((-1,3,-2)\) and perpendicular to the lines \(\frac{x+4}{1}=\frac{y}{2}=\frac{z-3}{3}\) and \(\frac{x+2}{-3}=\frac{y+5}{2}=\frac{z-6}{5}\) is
- A \(\vec{r}=(-3 \hat{i}+4 \hat{j}+15 \hat{k})+\lambda(-\hat{i}+3 \hat{j}-2 \hat{k})\)
- B \(\vec{r}=(-\hat{i}+3 \hat{j}-2 \hat{k})+\lambda(-3 \hat{i}+4 \hat{j}+15 \hat{k})\)
- C \(\vec{r}=2 \hat{i}-7 \hat{j}+4 \hat{k}+\lambda(-\hat{i}+3 \hat{j}-2 \hat{k})\)
- D \(\vec{r}=(-\hat{i}+3 \hat{j}-2 \hat{k})+\lambda(2 \hat{i}-7 \hat{j}+4 \hat{k})\)
Answer & Solution
Correct Answer
(D) \(\vec{r}=(-\hat{i}+3 \hat{j}-2 \hat{k})+\lambda(2 \hat{i}-7 \hat{j}+4 \hat{k})\)
Step-by-step Solution
Detailed explanation
Direction vectors of given lines: \(\vec{d_1} = \hat{i} + 2\hat{j} + 3\hat{k}\), \(\vec{d_2} = -3\hat{i} + 2\hat{j} + 5\hat{k}\) Direction vector of the required line:…
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