CUET · MATHS · PYQ PAPER 2023
The value of \(\int \frac{\cos x d x}{(1+\sin x)(2+\sin x)}\) is :
- A \(\log \left|\frac{1}{(1+\sin x)(2+\sin x)}\right|+C\)
- B \(\log \left|\frac{2+\cos x}{1+\cos x}\right|+C\)
- C \(\log \left|\frac{2+\sin x}{1+\sin x}\right|+C\)
- D \(\log \left|\frac{1+\sin x}{2+\sin x}\right|+C\)
Answer & Solution
Correct Answer
(D) \(\log \left|\frac{1+\sin x}{2+\sin x}\right|+C\)
Step-by-step Solution
Detailed explanation
Let \(u = \sin x\), \(du = \cos x dx\). \(\int \frac{du}{(1+u)(2+u)} = \int \left( \frac{1}{1+u} - \frac{1}{2+u} \right) du\) \(= \log|1+u| - \ln|2+u| + C\) \(= \log \left| \frac{1+u}{2+u} \right| + C\) \(= \log \left| \frac{1+\sin x}{2+\sin x} \right| + C\)
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