CUET · MATHS · PYQ PAPER 2023
The value of the integral \(\int\left(x^6+x^4\right) d\left(x^2\right)\) is equal to:
- A \(\frac{x^6}{6}+\frac{x^4}{4}+C\), where C is a constant
- B \(\frac{x^7}{7}+\frac{x^5}{5}+C\), where C is a constant
- C \(\frac{x^8}{4}+\frac{x^6}{3}+C\), where C is a constant
- D \(\frac{x^8}{6}+\frac{x^6}{6}+C\), where C is a constant
Answer & Solution
Correct Answer
(C) \(\frac{x^8}{4}+\frac{x^6}{3}+C\), where C is a constant
Step-by-step Solution
Detailed explanation
\(\int\left( (x^2)^3 + (x^2)^2 \right) d(x^2)\) \(= \frac{(x^2)^4}{4} + \frac{(x^2)^3}{3} + C\) \(= \frac{x^8}{4} + \frac{x^6}{3} + C\)
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