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CUET · MATHS · PYQ PAPER 2023

The value of the integral \(I=\int e^x\left(\tan ^{-1} x+\frac{1}{1+x^2}\right) d x\) is :

  1. A \(\frac{e^x}{1+x^2}+C\), where \(C\) is a constant
  2. B \(e^x \tan ^{-1} x+C\), where \(C\) is a constant
  3. C \(\frac{1}{1+x^2}+C\), where \(C\) is a constant
  4. D \(\tan ^{-1} x+C\), where \(C\) is a constant
Verified Solution

Answer & Solution

Correct Answer

(B) \(e^x \tan ^{-1} x+C\), where \(C\) is a constant

Step-by-step Solution

Detailed explanation

\(I=\int e^x\left(f(x)+f'(x)\right) dx = e^x f(x) + C\) Let \(f(x) = \tan^{-1} x\) Then \(f'(x) = \frac{1}{1+x^2}\) \(I = e^x \tan^{-1} x + C\)
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