CUET · MATHS · PYQ PAPER 2023
The value of the integral \(I=\int_{-1}^2|x| d x\) is :
- A \(0\)
- B \(\frac{1}{2}\)
- C \(\frac{ 5 }{ 2 }\)
- D \(\frac{3}{2}\)
Answer & Solution
Correct Answer
(C) \(\frac{ 5 }{ 2 }\)
Step-by-step Solution
Detailed explanation
\(I=\int_{-1}^0(-x)dx + \int_{0}^2 xdx\) \(I = \left[-\frac{x^2}{2}\right]_{-1}^0 + \left[\frac{x^2}{2}\right]_0^2\) \(I = \left(0 - \left(-\frac{1}{2}\right)\right) + \left(\frac{4}{2} - 0\right)\) \(I = \frac{1}{2} + 2 = \frac{5}{2}\)
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