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CUET · MATHS · PYQ PAPER 2023

The value of the integral \(I=\int_{-1}^2|x| d x\) is :

  1. A \(0\)
  2. B \(\frac{1}{2}\)
  3. C \(\frac{ 5 }{ 2 }\)
  4. D \(\frac{3}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{ 5 }{ 2 }\)

Step-by-step Solution

Detailed explanation

\(I=\int_{-1}^0(-x)dx + \int_{0}^2 xdx\) \(I = \left[-\frac{x^2}{2}\right]_{-1}^0 + \left[\frac{x^2}{2}\right]_0^2\) \(I = \left(0 - \left(-\frac{1}{2}\right)\right) + \left(\frac{4}{2} - 0\right)\) \(I = \frac{1}{2} + 2 = \frac{5}{2}\)