CUET · MATHS · PYQ PAPER 2023
The value of the integral \(I=\int_{-1}^1|x| d x\) is:
- A \(0\)
- B 1
- C \(\frac{1}{2}\)
- D 2
Answer & Solution
Correct Answer
(B) 1
Step-by-step Solution
Detailed explanation
\(I = \int_{-1}^1|x| d x = 2 \int_{0}^1 x d x\) \(= 2 \left[ \frac{x^2}{2} \right]_{0}^1 = 2 \left( \frac{1^2}{2} - \frac{0^2}{2} \right) = 1\)
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