CUET · MATHS · PYQ PAPER 2023
The value of the determinant \(\left|\begin{array}{ccc}a \cos \theta & b \sin \theta & 0 \\ -b \sin \theta & a \cos \theta & 0 \\ 0 & 0 & c\end{array}\right|\) is :
- A \(\left(a^2+b^2\right) c\)
- B \(\left(a^2 \cos ^2 \theta+b^2 \sin ^2 \theta\right) c\)
- C \(\left(a^2 \cos ^2 \theta-b^2 \sin ^2 \theta\right) c\)
- D \(\left(a^2+b^2\right) c^2\)
Answer & Solution
Correct Answer
(B) \(\left(a^2 \cos ^2 \theta+b^2 \sin ^2 \theta\right) c\)
Step-by-step Solution
Detailed explanation
\( \left| \begin{array}{ccc} a \cos \theta & b \sin \theta & 0 \\ -b \sin \theta & a \cos \theta & 0 \\ 0 & 0 & c \end{array} \right| = c \left| \begin{array}{cc} a \cos \theta & b \sin \theta \\ -b \sin \theta & a \cos \theta \end{array} \right| \)…
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