CUET · MATHS · PYQ PAPER 2025
The value of the definite integral \(I=\int_1^2 \frac{1}{x\left(1+x^2\right)} d x\) is:
- A \(\frac{ 3 }{ 2 }\)
- B \(\frac{3}{2} \log 2-\frac{1}{2} \log 5\)
- C \(\frac{5}{2} \log 3-\frac{1}{2} \log 5\)
- D \(\frac{5}{2} \log 3+\log 5\)
Answer & Solution
Correct Answer
(B) \(\frac{3}{2} \log 2-\frac{1}{2} \log 5\)
Step-by-step Solution
Detailed explanation
\(\frac{1}{x(1+x^2)} = \frac{1}{x} - \frac{x}{1+x^2}\) \(I = \int_1^2 \left(\frac{1}{x} - \frac{x}{1+x^2}\right) dx\) \(I = \left[\log|x| - \frac{1}{2} \log(1+x^2)\right]_1^2\) \(I = \left(\log 2 - \frac{1}{2} \log 5\right) - \left(\log 1 - \frac{1}{2} \log 2\right)\)…
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