CUET · MATHS · PYQ PAPER 2025
The value of \(k\) for which the lines \(\frac{2 x-3}{4}=\frac{3-y}{k}=\frac{z-2}{-2}\) and \(\frac{x-2}{1}=\frac{y}{4}=\frac{5-z}{3}\) are perpendicular to each other is :
- A \(\frac{5}{2}\)
- B \(-\frac{5}{2}\)
- C 2
- D \(-2\)
Answer & Solution
Correct Answer
(C) 2
Step-by-step Solution
Detailed explanation
Direction vector for the first line: \(\vec{d_1} = \langle 2, -k, -2 \rangle\) Direction vector for the second line: \(\vec{d_2} = \langle 1, 4, -3 \rangle\) For perpendicular lines, \(\vec{d_1} \cdot \vec{d_2} = 0\) \((2)(1) + (-k)(4) + (-2)(-3) = 0\) \(2 - 4k + 6 = 0\)…
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