CUET · MATHS · PYQ PAPER 2025
The value of \(k\) for which the function \(f(x)=\left\{\begin{array}{ll}\frac{1-\cos 8 x}{16 x^2} & , \text { if } x \neq 0 \\ k & , \text { if } x=0\end{array}\right.\) is continuous at \(x=0\) is :
- A \(0\)
- B 2
- C \(-2\)
- D 1
Answer & Solution
Correct Answer
(B) 2
Step-by-step Solution
Detailed explanation
For continuity at \(x=0\), \(\lim_{x \to 0} f(x) = f(0)\). \(\lim_{x \to 0} \frac{1-\cos 8 x}{16 x^2} = k\) \(\lim_{x \to 0} \frac{2 \sin^2(4x)}{16 x^2} = k\) \(\lim_{x \to 0} \frac{2 \cdot (4x)^2 \left(\frac{\sin 4x}{4x}\right)^2}{16 x^2} = k\)…
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