CUET · MATHS · PYQ PAPER 2023
The value of integral \(I=\int \frac{1-\sin x}{\cos ^2 x} d x\) is:
- A \(\tan x-\sec x+c\), where \(c\) is a constant
- B \(\sec x-\tan x+c\), where \(c\) is a constant
- C \(\sec x \tan x+c\), where \(c\) is a constant
- D \(\tan x+\sec x+c\), where \(c\) is a constant
Answer & Solution
Correct Answer
(A) \(\tan x-\sec x+c\), where \(c\) is a constant
Step-by-step Solution
Detailed explanation
\(I=\int \left(\frac{1}{\cos ^2 x}-\frac{\sin x}{\cos ^2 x}\right) d x\) \(I=\int \left(\sec ^2 x-\sec x \tan x\right) d x\) \(I=\tan x-\sec x+c\)
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