CUET · MATHS · PYQ PAPER 2023
The value of b , for which the function \(f(x)= \begin{cases} 5x - 4, & 0 < x \leq 1 \\ 4x^2 + 3bx, & 1 < x < 2 \end{cases}\), is continuous at every point of its domain is :
- A \(-1\)
- B \(0\)
- C 1
- D \(\frac{13}{3}\)
Answer & Solution
Correct Answer
(A) \(-1\)
Step-by-step Solution
Detailed explanation
\(5(1) - 4 = 4(1)^2 + 3b(1)\) \(1 = 4 + 3b\) \(3b = -3\) \(b = -1\)
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