CUET · MATHS · PYQ PAPER 2023
The value of \(\left|\begin{array}{lll}1 & b & c+a \\ 1 & c & a+b\end{array}\right|\) is
- A \(0\)
- B \((a+b+c)\)
- C \((a-b)(b-c)(c-a)\)
- D \(a^2+b^2+c^2\)
Answer & Solution
Correct Answer
(A) \(0\)
Step-by-step Solution
Detailed explanation
\(\left|\begin{array}{lll}1 & b & c+a \\ 1 & c & a+b \\ 1 & a & b+c\end{array}\right|\) \(C_3 \rightarrow C_3 + C_2\) \(\left|\begin{array}{lll}1 & b & c+a+b \\ 1 & c & a+b+c \\ 1 & a & b+c+a\end{array}\right|\)…
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