CUET · MATHS · PYQ PAPER 2023
The value of \(\lambda\) and \(\mu\) if \((2 \hat{i}+6 \hat{j}+27 \hat{k}) \times(\hat{i}+\lambda \hat{j}+\mu \hat{k})=\overrightarrow{0}\) are respectively :
- A \(3, \frac{27}{2}\)
- B \(-\frac{27}{2}, 3\)
- C \(-1, \frac{11}{3}\)
- D \(-\frac{5}{3}, \frac{7}{3}\)
Answer & Solution
Correct Answer
(A) \(3, \frac{27}{2}\)
Step-by-step Solution
Detailed explanation
\( (2 \hat{i}+6 \hat{j}+27 \hat{k}) \times(\hat{i}+\lambda \hat{j}+\mu \hat{k})=\overrightarrow{0} \implies \text{vectors are parallel} \) \(\frac{2}{1} = \frac{6}{\lambda} = \frac{27}{\mu}\) \(\frac{2}{1} = \frac{6}{\lambda} \implies 2\lambda = 6 \implies \lambda = 3\)…
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