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CUET · MATHS · PYQ PAPER 2025

The value of \(\int_2^4 \frac{x}{x^2+1} d x\) is equal to :

  1. A \(\frac{1}{2} \log _e\left(\frac{17}{5}\right)\)
  2. B \(\frac{1}{5} \log _e\left(\frac{17}{5}\right)\)
  3. C \(\log _e\left(\frac{17}{5}\right)\)
  4. D \(2 \log _e\left(\frac{17}{5}\right)\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{1}{2} \log _e\left(\frac{17}{5}\right)\)

Step-by-step Solution

Detailed explanation

\( \int_2^4 \frac{x}{x^2+1} d x = \frac{1}{2} \int_2^4 \frac{2x}{x^2+1} d x \) \( = \left[ \frac{1}{2} \log(x^2+1) \right]_2^4 \) \( = \frac{1}{2} (\log(4^2+1) - \log(2^2+1)) \) \( = \frac{1}{2} (\log(17) - \ln(5)) \) \( = \frac{1}{2} \log\left(\frac{17}{5}\right) \)