CUET · MATHS · PYQ PAPER 2025
The value of \(\int_2^4 \frac{x}{x^2+1} d x\) is equal to :
- A \(\frac{1}{2} \log _e\left(\frac{17}{5}\right)\)
- B \(\frac{1}{5} \log _e\left(\frac{17}{5}\right)\)
- C \(\log _e\left(\frac{17}{5}\right)\)
- D \(2 \log _e\left(\frac{17}{5}\right)\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{2} \log _e\left(\frac{17}{5}\right)\)
Step-by-step Solution
Detailed explanation
\( \int_2^4 \frac{x}{x^2+1} d x = \frac{1}{2} \int_2^4 \frac{2x}{x^2+1} d x \) \( = \left[ \frac{1}{2} \log(x^2+1) \right]_2^4 \) \( = \frac{1}{2} (\log(4^2+1) - \log(2^2+1)) \) \( = \frac{1}{2} (\log(17) - \ln(5)) \) \( = \frac{1}{2} \log\left(\frac{17}{5}\right) \)
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