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CUET · MATHS · PYQ PAPER 2025

The value of \(\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}}(\sin |x|+\cos |x|) d x\), is equal to:

  1. A 0
  2. B 1
  3. C 2
  4. D 4
Verified Solution

Answer & Solution

Correct Answer

(D) 4

Step-by-step Solution

Detailed explanation

\(\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}}(\sin |x|+\cos |x|) d x = 2 \int_{0}^{\frac{\pi}{2}}(\sin x+\cos x) d x\) \(= 2 [-\cos x+\sin x]_{0}^{\frac{\pi}{2}}\) \(= 2 [(-\cos \frac{\pi}{2}+\sin \frac{\pi}{2})-(-\cos 0+\sin 0)]\) \(= 2 [(0+1)-(-1+0)]\) \(= 2 [1-(-1)]\)…
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