CUET · MATHS · PYQ PAPER 2025
The value of \(\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}}(\sin |x|+\cos |x|) d x\), is equal to:
- A 0
- B 1
- C 2
- D 4
Answer & Solution
Correct Answer
(D) 4
Step-by-step Solution
Detailed explanation
\(\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}}(\sin |x|+\cos |x|) d x = 2 \int_{0}^{\frac{\pi}{2}}(\sin x+\cos x) d x\) \(= 2 [-\cos x+\sin x]_{0}^{\frac{\pi}{2}}\) \(= 2 [(-\cos \frac{\pi}{2}+\sin \frac{\pi}{2})-(-\cos 0+\sin 0)]\) \(= 2 [(0+1)-(-1+0)]\) \(= 2 [1-(-1)]\)…
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