CUET · MATHS · PYQ PAPER 2025
The value of \(\int_{\frac{-\pi}{2}}^{\pi / 2}\left(x^5+x^3 \cos x\right) d x\) is :
- A 0
- B \(-1\)
- C \(\pi\)
- D 1
Answer & Solution
Correct Answer
(A) 0
Step-by-step Solution
Detailed explanation
\(f(x) = x^5+x^3 \cos x\) \(f(-x) = (-x)^5 + (-x)^3 \cos(-x) = -x^5 - x^3 \cos x = -(x^5+x^3 \cos x) = -f(x)\) Since \(f(x)\) is an odd function, \(\int_{-a}^{a} f(x) dx = 0\) \(\int_{\frac{-\pi}{2}}^{\pi / 2}\left(x^5+x^3 \cos x\right) d x = 0\)
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