CUET · MATHS · PYQ PAPER 2023
The value of \(\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}}\left(x^3+x \cos x+\tan ^5 x\right) d x\) is:
- A \(0\)
- B 1
- C 2
- D \(\pi\)
Answer & Solution
Correct Answer
(A) \(0\)
Step-by-step Solution
Detailed explanation
\(f(x) = x^3+x \cos x+\tan ^5 x\) \(f(-x) = (-x)^3+(-x) \cos(-x)+\tan ^5 (-x) = -x^3-x \cos x-\tan ^5 x = -f(x)\) Since \(f(x)\) is an odd function and the interval \(\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]\) is symmetric, \(\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}} f(x) d x = 0\)
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