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CUET · MATHS · PYQ PAPER 2023

The value of \(\int \frac{1}{\sqrt{x^2+8 x+9}} d x\) is(Given \(C\) constant of integration):

  1. A \(\log \left[(x+4)+\sqrt{x^2+8 x+9}\right]+C\)
  2. B \(\log \left[(x+4)-\sqrt{x^2+8 x+9}\right]+C\)
  3. C \(\log \left[(x-4)+\sqrt{x^2-8 x+9}\right]+C\)
  4. D \(\log \left[(x-4)-\sqrt{x^2+8 x-9}\right]+C\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\log \left[(x+4)+\sqrt{x^2+8 x+9}\right]+C\)

Step-by-step Solution

Detailed explanation

\(\int \frac{1}{\sqrt{x^2+8 x+9}} d x = \int \frac{1}{\sqrt{(x+4)^2 - 7}} d x\) \(= \log \left|(x+4)+\sqrt{(x+4)^2 - 7}\right|+C\) \(= \log \left[(x+4)+\sqrt{x^2+8 x+9}\right]+C\)