CUET · MATHS · PYQ PAPER 2023
The value of \(\int_1^2 \frac{\sqrt{x}}{\sqrt{3-x}+\sqrt{x}} d x\) is:
- A 1
- B \(\frac{1}{2}\)
- C \(\frac{1}{3}\)
- D \(\frac{1}{4}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
\(I = \int_1^2 \frac{\sqrt{x}}{\sqrt{3-x}+\sqrt{x}} d x\) \(I = \int_1^2 \frac{\sqrt{3-x}}{\sqrt{3-(3-x)}+\sqrt{3-x}} d x = \int_1^2 \frac{\sqrt{3-x}}{\sqrt{x}+\sqrt{3-x}} d x\)…
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