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CUET · MATHS · PYQ PAPER 2023

The value of \(\int_1^2 \frac{\sqrt{x}}{\sqrt{3-x}+\sqrt{x}} d x\) is:

  1. A 1
  2. B \(\frac{1}{2}\)
  3. C \(\frac{1}{3}\)
  4. D \(\frac{1}{4}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{1}{2}\)

Step-by-step Solution

Detailed explanation

\(I = \int_1^2 \frac{\sqrt{x}}{\sqrt{3-x}+\sqrt{x}} d x\) \(I = \int_1^2 \frac{\sqrt{3-x}}{\sqrt{3-(3-x)}+\sqrt{3-x}} d x = \int_1^2 \frac{\sqrt{3-x}}{\sqrt{x}+\sqrt{3-x}} d x\)…
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