CUET · MATHS · PYQ PAPER 2023
The value of \(\int_{-1}^1 x^2[x] d x\) is:
- A \(\frac{1}{3}\)
- B \(\frac{2}{3}\)
- C 1
- D \(-\frac{1}{3}\)
Answer & Solution
Correct Answer
(D) \(-\frac{1}{3}\)
Step-by-step Solution
Detailed explanation
\(\int_{-1}^1 x^2[x] d x = \int_{-1}^0 x^2(-1) d x + \int_{0}^1 x^2(0) d x\) \(= -\int_{-1}^0 x^2 d x + 0\) \(= -\left[\frac{x^3}{3}\right]_{-1}^0\) \(= -\left(\frac{0^3}{3} - \frac{(-1)^3}{3}\right)\) \(= -\left(0 - \left(-\frac{1}{3}\right)\right)\) \(= -\frac{1}{3}\)
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