CUET · MATHS · PYQ PAPER 2025
The value of \(\int_0^1 \log _e\left(\frac{1}{x}-1\right) d x\) is :
- A 1
- B 0
- C \(\frac{3}{2}\)
- D \(\log 2\)
Answer & Solution
Correct Answer
(B) 0
Step-by-step Solution
Detailed explanation
\(I = \int_0^1 \log _e\left(\frac{1-x}{x}\right) d x\) Using \(\int_0^a f(x) dx = \int_0^a f(a-x) dx\): \(I = \int_0^1 \log _e\left(\frac{1-(1-x)}{1-x}\right) d x = \int_0^1 \log _e\left(\frac{x}{1-x}\right) d x\) \(I = \int_0^1 -\log _e\left(\frac{1-x}{x}\right) d x = -I\)…
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