CUET · MATHS · PYQ PAPER 2025
The speed of a motorboat in still water and that of the current of water is in a ratio of \(27: 5\).
The boat goes along the current from point \(A\) to point \(B\) in 3 hours 40 minutes.
How much time will it take to come back from \(B\) to \(A\)?
- A 5 hours 20 minutes
- B 5 hours 40 minutes
- C 3 hours 20 minutes
- D 6 hours 20 minutes
Answer & Solution
Correct Answer
(A) 5 hours 20 minutes
Step-by-step Solution
Detailed explanation
Let \(v_b\) be boat speed and \(v_c\) be current speed. \(\frac{v_b}{v_c} = \frac{27}{5}\) \(v_{down} = v_b + v_c = 27k + 5k = 32k\) \(v_{up} = v_b - v_c = 27k - 5k = 22k\) \(t_{down} = 3\) hrs \(40\) min \( = 3 + \frac{40}{60} = \frac{11}{3}\) hrs…
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