CUET · MATHS · PYQ PAPER 2025
The solution of the differential equation \(\log _e\left(\frac{d y}{d x}\right)=3 x+4 y\) is given by:
- A \(4 e^{3 x}+3 e^{-4 y}+C=0\), where C is constant of integration
- B \(3 e^{3 x}+4 e^{-4 y}+C=0\), where C is constant of integration
- C \(4 e^{-3 x}+3 e^{4 y}+C=0\), where C is constant of integration
- D \(3 e^{-3 a}+4 e^{4 y}+C=0\), where \(C\) is constant of integration
Answer & Solution
Correct Answer
(A) \(4 e^{3 x}+3 e^{-4 y}+C=0\), where C is constant of integration
Step-by-step Solution
Detailed explanation
\(\frac{d y}{d x} = e^{3x+4y}\) \(e^{-4y} dy = e^{3x} dx\) \(\int e^{-4y} dy = \int e^{3x} dx\) \(\frac{e^{-4y}}{-4} = \frac{e^{3x}}{3} + C_1\) \(3e^{-4y} = -4e^{3x} - 12C_1\) \(4e^{3x} + 3e^{-4y} + C = 0\)
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