CUET · MATHS · PYQ PAPER 2023
The solution of the differential equation \(\frac{d y}{d x}=\frac{3 e^{2 x}+3 e^{4 x}}{e^x+e^{-x}}\) is:
- A \(y=\left(e^x+e^{-x}\right)+C\)
- B \(y=C e^x\)
- C \(y=e^{3 x}+C\)
- D \(y=3 e^{3 x}+C\)
Answer & Solution
Correct Answer
(C) \(y=e^{3 x}+C\)
Step-by-step Solution
Detailed explanation
\(\frac{d y}{d x}=\frac{3 e^{2 x}(1+e^{2 x})}{e^{-x}(e^{2x}+1)}\) \(\frac{d y}{d x}=3 e^{2 x} e^x\) \(\frac{d y}{d x}=3 e^{3 x}\) \(y=\int 3 e^{3 x} dx\) \(y=3\left(\frac{e^{3 x}}{3}\right)+C\) \(y=e^{3 x}+C\)
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