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The solution of the differential equation \(\frac{d y}{d x}-\frac{y}{x}=2 \log _e x\)
- A \(y=x \log _e x+C\) : C is an arbitrary constant
- B \(y=x\left(\log _e x+C\right)\) : C is an arbitrary constant
- C \(y=x\left(\left(\log _e x\right)^2+C\right)\) : C is an arbitrary constant
- D \(y=x\left(2\left(\log _e x\right)^2+C\right)\) : C is an arbitrary constant
Answer & Solution
Correct Answer
(C) \(y=x\left(\left(\log _e x\right)^2+C\right)\) : C is an arbitrary constant
Step-by-step Solution
Detailed explanation
Integrating factor \(IF = e^{\int -\frac{1}{x} dx} = e^{-\log_e x} = \frac{1}{x}\) Multiplying by \(IF\): \(\frac{d}{dx}\left(y \cdot \frac{1}{x}\right) = \frac{2 \log_e x}{x}\) Integrating both sides: \(\frac{y}{x} = \int \frac{2 \log_e x}{x} dx\) Let \(u=\log_e x\),…
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