CUET · MATHS · PYQ PAPER 2025
The solution of the differential equation \(\frac{d r}{d t}=-r t, r(0)=r_0\) is
- A \(r=r_0 e^{t^2 / 2}\)
- B \(r=-r_0 e^{t^2 / 2}\)
- C \(r=r_0 e^{-t^2 / 2}\)
- D \(r=-r_0 e^{-t^2 / 2}\)
Answer & Solution
Correct Answer
(C) \(r=r_0 e^{-t^2 / 2}\)
Step-by-step Solution
Detailed explanation
\(\int \frac{dr}{r} = \int -t \, dt\) \(\ln|r| = -\frac{t^2}{2} + C\) \(r = A e^{-t^2/2}\) \(r_0 = A e^{-0^2/2} \Rightarrow A = r_0\) \(r = r_0 e^{-t^2/2}\)
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